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3/4(x-12)+4=2/3(3x-6)
We move all terms to the left:
3/4(x-12)+4-(2/3(3x-6))=0
Domain of the equation: 4(x-12)!=0
x∈R
Domain of the equation: 3(3x-6))!=0We calculate fractions
x∈R
(9x3/(4(x-12)*3(3x-6)))+(-8xx/(4(x-12)*3(3x-6)))+4=0
We calculate terms in parentheses: +(9x3/(4(x-12)*3(3x-6))), so:
9x3/(4(x-12)*3(3x-6))
We multiply all the terms by the denominator
9x3
We add all the numbers together, and all the variables
9x^3
We do not support expression: x^3
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