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3/4(8x-16)=2/3(6x+9)
We move all terms to the left:
3/4(8x-16)-(2/3(6x+9))=0
Domain of the equation: 4(8x-16)!=0
x∈R
Domain of the equation: 3(6x+9))!=0We calculate fractions
x∈R
(9x6/(4(8x-16)*3(6x+9)))+(-8x8/(4(8x-16)*3(6x+9)))=0
We calculate terms in parentheses: +(9x6/(4(8x-16)*3(6x+9))), so:
9x6/(4(8x-16)*3(6x+9))
We multiply all the terms by the denominator
9x6
We add all the numbers together, and all the variables
9x^6
We do not support expression: x^6
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