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-3(2x-1)-4=(x+1)-2
We move all terms to the left:
-3(2x-1)-4-((x+1)-2)=0
We multiply parentheses
-6x-((x+1)-2)+3-4=0
We calculate terms in parentheses: -((x+1)-2), so:We add all the numbers together, and all the variables
(x+1)-2
We get rid of parentheses
x+1-2
We add all the numbers together, and all the variables
x-1
Back to the equation:
-(x-1)
-6x-(x-1)-1=0
We get rid of parentheses
-6x-x+1-1=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
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