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5(x-3)+7=1/2(10x+16)
We move all terms to the left:
5(x-3)+7-(1/2(10x+16))=0
Domain of the equation: 2(10x+16))!=0We multiply parentheses
x∈R
5x-(1/2(10x+16))-15+7=0
We multiply all the terms by the denominator
5x*2(10x+16))-(1-15*2(10x+16))+7*2(10x+16))=0
We add all the numbers together, and all the variables
5x*2(10x+16))-(1-15*2(10x+16))+7*2(10x=0
Wy multiply elements
10x^2(1-60x^2(1=0
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