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3/2x-6=60-48x
We move all terms to the left:
3/2x-6-(60-48x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3/2x-(-48x+60)-6=0
We get rid of parentheses
3/2x+48x-60-6=0
We multiply all the terms by the denominator
48x*2x-60*2x-6*2x+3=0
Wy multiply elements
96x^2-120x-12x+3=0
We add all the numbers together, and all the variables
96x^2-132x+3=0
a = 96; b = -132; c = +3;
Δ = b2-4ac
Δ = -1322-4·96·3
Δ = 16272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16272}=\sqrt{144*113}=\sqrt{144}*\sqrt{113}=12\sqrt{113}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-12\sqrt{113}}{2*96}=\frac{132-12\sqrt{113}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+12\sqrt{113}}{2*96}=\frac{132+12\sqrt{113}}{192} $
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