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2/t-2-t+1/t+4=0
Domain of the equation: t!=0We add all the numbers together, and all the variables
t∈R
-1t+2/t+1/t+2=0
We multiply all the terms by the denominator
-1t*t+2*t+2+1=0
We add all the numbers together, and all the variables
2t-1t*t+3=0
Wy multiply elements
-1t^2+2t+3=0
a = -1; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-1)·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*-1}=\frac{-6}{-2} =+3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*-1}=\frac{2}{-2} =-1 $
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