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3/2x+5=8/5x
We move all terms to the left:
3/2x+5-(8/5x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/2x-(+8/5x)+5=0
We get rid of parentheses
3/2x-8/5x+5=0
We calculate fractions
15x/10x^2+(-16x)/10x^2+5=0
We multiply all the terms by the denominator
15x+(-16x)+5*10x^2=0
Wy multiply elements
50x^2+15x+(-16x)=0
We get rid of parentheses
50x^2+15x-16x=0
We add all the numbers together, and all the variables
50x^2-1x=0
a = 50; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·50·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*50}=\frac{0}{100} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*50}=\frac{2}{100} =1/50 $
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