(2x-3)(x-3)=(x-1)(2x-8)+6

Solution for (2x-3)(x-3)=(x-1)(2x-8)+6 equation:

(2x-3)(x-3)=(x-1)(2x-8)+6

We move all terms to the left:

(2x-3)(x-3)-((x-1)(2x-8)+6)=0

We multiply parentheses ..

(+2x^2-6x-3x+9)-((x-1)(2x-8)+6)=0


We calculate terms in parentheses: -((x-1)(2x-8)+6), so:

(x-1)(2x-8)+6

We multiply parentheses ..

(+2x^2-8x-2x+8)+6

We get rid of parentheses

2x^2-8x-2x+8+6

We add all the numbers together, and all the variables

2x^2-10x+14

Back to the equation:

-(2x^2-10x+14)


We get rid of parentheses

2x^2-2x^2-6x-3x+10x+9-14=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5