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6x-(5x+5)=-8-2(2x+12)
We move all terms to the left:
6x-(5x+5)-(-8-2(2x+12))=0
We get rid of parentheses
6x-5x-(-8-2(2x+12))-5=0
We calculate terms in parentheses: -(-8-2(2x+12)), so:We add all the numbers together, and all the variables
-8-2(2x+12)
determiningTheFunctionDomain -2(2x+12)-8
We multiply parentheses
-4x-24-8
We add all the numbers together, and all the variables
-4x-32
Back to the equation:
-(-4x-32)
x-(-4x-32)-5=0
We get rid of parentheses
x+4x+32-5=0
We add all the numbers together, and all the variables
5x+27=0
We move all terms containing x to the left, all other terms to the right
5x=-27
x=-27/5
x=-5+2/5
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