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3/2x+2=2x/x+1
We move all terms to the left:
3/2x+2-(2x/x+1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+1)!=0We get rid of parentheses
x∈R
3/2x-2x/x-1+2=0
We calculate fractions
(-4x^2)/2x^2+3x/2x^2-1+2=0
We add all the numbers together, and all the variables
(-4x^2)/2x^2+3x/2x^2+1=0
We multiply all the terms by the denominator
(-4x^2)+3x+1*2x^2=0
Wy multiply elements
(-4x^2)+2x^2+3x=0
We get rid of parentheses
-4x^2+2x^2+3x=0
We add all the numbers together, and all the variables
-2x^2+3x=0
a = -2; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-2)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-2}=\frac{-6}{-4} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-2}=\frac{0}{-4} =0 $
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