7(3x-4)=16-x

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Solution for 7(3x-4)=16-x equation: 



7(3x-4)=16-x

We move all terms to the left:

7(3x-4)-(16-x)=0

We add all the numbers together, and all the variables

7(3x-4)-(-1x+16)=0

We multiply parentheses

21x-(-1x+16)-28=0

We get rid of parentheses

21x+1x-16-28=0

We add all the numbers together, and all the variables

22x-44=0

We move all terms containing x to the left, all other terms to the right

22x=44

x=44/22

x=2

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