2(4y-2)=-28

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Solution for 2(4y-2)=-28 equation: 



2(4y-2)=-28

We move all terms to the left:

2(4y-2)-(-28)=0

We add all the numbers together, and all the variables

2(4y-2)+28=0

We multiply parentheses

8y-4+28=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

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