3/2(4x-6)-x(3-x)=1/3x(3x+6)

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Solution for 3/2(4x-6)-x(3-x)=1/3x(3x+6) equation: 



3/2(4x-6)-x(3-x)=1/3x(3x+6)

We move all terms to the left:

3/2(4x-6)-x(3-x)-(1/3x(3x+6))=0



Domain of the equation: 2(4x-6)!=0

x∈R





Domain of the equation: 3x(3x+6))!=0

x∈R



We add all the numbers together, and all the variables

3/2(4x-6)-x(-1x+3)-(1/3x(3x+6))=0

We multiply parentheses

1x^2+3/2(4x-6)-3x-(1/3x(3x+6))=0

We calculate fractions


1x^2-3x+(9x3/(2(4x-6)*3x(3x+6)))+(-2x4/(2(4x-6)*3x(3x+6)))=0



We calculate terms in parentheses: +(9x3/(2(4x-6)*3x(3x+6))), so:

9x3/(2(4x-6)*3x(3x+6))

We multiply all the terms by the denominator


9x3

We add all the numbers together, and all the variables

9x^3

We do not support expression: x^3

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