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8+6(x-6)=10-3(x-4)
We move all terms to the left:
8+6(x-6)-(10-3(x-4))=0
We multiply parentheses
6x-(10-3(x-4))-36+8=0
We calculate terms in parentheses: -(10-3(x-4)), so:We add all the numbers together, and all the variables
10-3(x-4)
determiningTheFunctionDomain -3(x-4)+10
We multiply parentheses
-3x+12+10
We add all the numbers together, and all the variables
-3x+22
Back to the equation:
-(-3x+22)
6x-(-3x+22)-28=0
We get rid of parentheses
6x+3x-22-28=0
We add all the numbers together, and all the variables
9x-50=0
We move all terms containing x to the left, all other terms to the right
9x=50
x=50/9
x=5+5/9
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