(6t-4)=3(t-1)+3

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Solution for (6t-4)=3(t-1)+3 equation: 



(6t-4)=3(t-1)+3

We move all terms to the left:

(6t-4)-(3(t-1)+3)=0

We get rid of parentheses

6t-(3(t-1)+3)-4=0



We calculate terms in parentheses: -(3(t-1)+3), so:

3(t-1)+3

We multiply parentheses

3t-3+3

We add all the numbers together, and all the variables

3t

Back to the equation:

-(3t)



We add all the numbers together, and all the variables

3t-4=0

We move all terms containing t to the left, all other terms to the right

3t=4

t=4/3

t=1+1/3

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