3/(x-2)+2/(x-1)=5

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Solution for 3/(x-2)+2/(x-1)=5 equation: 



3/(x-2)+2/(x-1)=5

We move all terms to the left:

3/(x-2)+2/(x-1)-(5)=0



Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R





Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R



We calculate fractions


(3x-3)/((x-2)*(x-1))+(2x-4)/((x-2)*(x-1))-5=0



We calculate terms in parentheses: +(3x-3)/((x-2)*(x-1)), so:

3x-3)/((x-2)*(x-1)

We multiply all the terms by the denominator


3x*((x-2)*(x-1)-3)

Back to the equation:

+(3x*((x-2)*(x-1)-3))





We calculate terms in parentheses: +(2x-4)/((x-2)*(x-1)), so:

2x-4)/((x-2)*(x-1)

We multiply all the terms by the denominator


2x*((x-2)*(x-1)-4)

Back to the equation:

+(2x*((x-2)*(x-1)-4))





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





We calculate terms in parentheses: +(2x*((x-2)*(x-1)-4)), so:

2x*((x-2)*(x-1)-4)





We calculate terms in parentheses: +(3x*((x-2)*(x-1)-3)), so:

3x*((x-2)*(x-1)-3)





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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