4(2b-3)+-16=49(2b-4)

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Solution for 4(2b-3)+-16=49(2b-4) equation: 



4(2b-3)+-16=49(2b-4)

We move all terms to the left:

4(2b-3)+-16-(49(2b-4))=0

We add all the numbers together, and all the variables

4(2b-3)-(49(2b-4))=0

We multiply parentheses

8b-(49(2b-4))-12=0



We calculate terms in parentheses: -(49(2b-4)), so:

49(2b-4)

We multiply parentheses

98b-196

Back to the equation:

-(98b-196)



We get rid of parentheses

8b-98b+196-12=0

We add all the numbers together, and all the variables

-90b+184=0

We move all terms containing b to the left, all other terms to the right

-90b=-184

b=-184/-90

b=2+2/45

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