-3(4-2b)=2(2b-3)

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Solution for -3(4-2b)=2(2b-3) equation: 



-3(4-2b)=2(2b-3)

We move all terms to the left:

-3(4-2b)-(2(2b-3))=0

We add all the numbers together, and all the variables

-3(-2b+4)-(2(2b-3))=0

We multiply parentheses

6b-(2(2b-3))-12=0



We calculate terms in parentheses: -(2(2b-3)), so:

2(2b-3)

We multiply parentheses

4b-6

Back to the equation:

-(4b-6)



We get rid of parentheses

6b-4b+6-12=0

We add all the numbers together, and all the variables

2b-6=0

We move all terms containing b to the left, all other terms to the right

2b=6

b=6/2

b=3

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