3/(x+3)=7/(5+x)

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Solution for 3/(x+3)=7/(5+x) equation: 



3/(x+3)=7/(5+x)

We move all terms to the left:

3/(x+3)-(7/(5+x))=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (5+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

3/(x+3)-(7/(x+5))=0

We calculate fractions


3x/((x+3)*(x+5)))+(-(7*(x+3))/((x+3)*(x+5)))=0



We calculate terms in parentheses: -(7*(x+3))/((x+3)*(x+5))), so:

7*(x+3))/((x+3)*(x+5))

We multiply all the terms by the denominator


7*(x+3))

We multiply parentheses

7x+

We add all the numbers together, and all the variables

7x

Back to the equation:

-(7x)



We add all the numbers together, and all the variables

-7x+3x/((x+3)*(x+5)))+(=0

We multiply all the terms by the denominator


-7x*((x+3)*(x+5)))+(+3x=0

We add all the numbers together, and all the variables

3x-7x*((x+3)*(x+5)))+(=0

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