(8x-28)=(12x-88)

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Solution for (8x-28)=(12x-88) equation: 



(8x-28)=(12x-88)

We move all terms to the left:

(8x-28)-((12x-88))=0

We get rid of parentheses

8x-((12x-88))-28=0



We calculate terms in parentheses: -((12x-88)), so:

(12x-88)

We get rid of parentheses

12x-88

Back to the equation:

-(12x-88)



We get rid of parentheses

8x-12x+88-28=0

We add all the numbers together, and all the variables

-4x+60=0

We move all terms containing x to the left, all other terms to the right

-4x=-60

x=-60/-4

x=+15

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