1/2(x+1)=1/3(2x-5)=

Solution for 1/2(x+1)=1/3(2x-5)= equation:

1/2(x+1)=1/3(2x-5)=

We move all terms to the left:

1/2(x+1)-(1/3(2x-5))=0


Domain of the equation: 2(x+1)!=0

x∈R



Domain of the equation: 3(2x-5))!=0

x∈R


We calculate fractions


(3x2/(2(x+1)*3(2x-5)))+(-2xx/(2(x+1)*3(2x-5)))=0


We calculate terms in parentheses: +(3x2/(2(x+1)*3(2x-5))), so:

3x2/(2(x+1)*3(2x-5))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)



We calculate terms in parentheses: +(-2xx/(2(x+1)*3(2x-5))), so:

-2xx/(2(x+1)*3(2x-5))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

3x^2-2xx=0