(4x-27)(3x+16)=

Solution for (4x-27)(3x+16)= equation:

(4x-27)(3x+16)=

We move all terms to the left:

(4x-27)(3x+16)-()=0

We add all the numbers together, and all the variables

(4x-27)(3x+16)=0

We multiply parentheses ..

(+12x^2+64x-81x-432)=0

We get rid of parentheses

12x^2+64x-81x-432=0

We add all the numbers together, and all the variables

12x^2-17x-432=0

a = 12; b = -17; c = -432;
Δ = b2-4ac
Δ = -172-4·12·(-432)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-145}{2*12}=\frac{-128}{24}
=-5+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+145}{2*12}=\frac{162}{24}
=6+3/4
$