3-8=m(m+1)

Solution for 3-8=m(m+1) equation:

3-8=m(m+1)

We move all terms to the left:

3-8-(m(m+1))=0

We add all the numbers together, and all the variables

-(m(m+1))-5=0


We calculate terms in parentheses: -(m(m+1)), so:

m(m+1)

We multiply parentheses

m^2+m

Back to the equation:

-(m^2+m)


We get rid of parentheses

-m^2-m-5=0

We add all the numbers together, and all the variables

-1m^2-1m-5=0

a = -1; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation