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6p^2-4p-3p=2=0
We move all terms to the left:
6p^2-4p-3p-(2)=0
We add all the numbers together, and all the variables
6p^2-7p-2=0
a = 6; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·6·(-2)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{97}}{2*6}=\frac{7-\sqrt{97}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{97}}{2*6}=\frac{7+\sqrt{97}}{12} $
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