If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/3=(x-2)/(2x+1)
We move all terms to the left:
2/3-((x-2)/(2x+1))=0
Domain of the equation: (2x+1))!=0We calculate fractions
x∈R
(-((x-2)*3)/6x+4x/6x=0
We can not solve this equation
| (n-3)(n+4)=10 | | 8x+12=-3+34 | | £29.50x10= | | 1÷4y-4=16 | | 7+x+9=22 | | x/5=-6+0.5x | | 5+x+20+13=9 | | 4j−-24=84 | | 5r+17=-68 | | 4(5x-6)=4(9x+4) | | 6q=2(3q) | | 9x-2+6x=4x+4-6x | | 7x+21=10x+3 | | 4(5x-2)=8 | | 3t-5/4-1=4t-3/5 | | 10x+3=4x-3 | | 3(16-3x)-10(1+x)+x2=(x-1)(x+3) | | 8m+4=5m+14 | | 2p+11=7 | | 7m-3=-10 | | 3÷-8+m=1÷4 | | 4/7(w+1)=-10+7/3w | | 10x=1,000. | | 10x=0.01. | | 10x=0.0001. | | 1/3(x)=24 | | 5x2=18 | | 1/3(x)=25 | | 18x/(18x+136)=21/100 | | K-3x=24 | | 1-2x=2x+17 | | y^2+y^2=28 |