3-4(6-7x)=3(8x-11)-4(9x-25)

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Solution for 3-4(6-7x)=3(8x-11)-4(9x-25) equation: 



3-4(6-7x)=3(8x-11)-4(9x-25)

We move all terms to the left:

3-4(6-7x)-(3(8x-11)-4(9x-25))=0

We add all the numbers together, and all the variables

-4(-7x+6)-(3(8x-11)-4(9x-25))+3=0

We multiply parentheses

28x-(3(8x-11)-4(9x-25))-24+3=0



We calculate terms in parentheses: -(3(8x-11)-4(9x-25)), so:

3(8x-11)-4(9x-25)

We multiply parentheses

24x-36x-33+100

We add all the numbers together, and all the variables

-12x+67

Back to the equation:

-(-12x+67)



We add all the numbers together, and all the variables

28x-(-12x+67)-21=0

We get rid of parentheses

28x+12x-67-21=0

We add all the numbers together, and all the variables

40x-88=0

We move all terms containing x to the left, all other terms to the right

40x=88

x=88/40

x=2+1/5

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