(3x+18)=(10x-14)+(2x-8)

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Solution for (3x+18)=(10x-14)+(2x-8) equation: 



(3x+18)=(10x-14)+(2x-8)

We move all terms to the left:

(3x+18)-((10x-14)+(2x-8))=0

We get rid of parentheses

3x-((10x-14)+(2x-8))+18=0



We calculate terms in parentheses: -((10x-14)+(2x-8)), so:

(10x-14)+(2x-8)

We get rid of parentheses

10x+2x-14-8

We add all the numbers together, and all the variables

12x-22

Back to the equation:

-(12x-22)



We get rid of parentheses

3x-12x+22+18=0

We add all the numbers together, and all the variables

-9x+40=0

We move all terms containing x to the left, all other terms to the right

-9x=-40

x=-40/-9

x=4+4/9

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