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(3x-5)+(7x+2)+(-12+5x)=180
We move all terms to the left:
(3x-5)+(7x+2)+(-12+5x)-(180)=0
We add all the numbers together, and all the variables
(3x-5)+(7x+2)+(5x-12)-180=0
We get rid of parentheses
3x+7x+5x-5+2-12-180=0
We add all the numbers together, and all the variables
15x-195=0
We move all terms containing x to the left, all other terms to the right
15x=195
x=195/15
x=13
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