5(5z+2)+9(3z-2)=2

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Solution for 5(5z+2)+9(3z-2)=2 equation: 



5(5z+2)+9(3z-2)=2

We move all terms to the left:

5(5z+2)+9(3z-2)-(2)=0

We multiply parentheses

25z+27z+10-18-2=0

We add all the numbers together, and all the variables

52z-10=0

We move all terms containing z to the left, all other terms to the right

52z=10

z=10/52

z=5/26

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