3-(3c+5)=2(10-c)

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Solution for 3-(3c+5)=2(10-c) equation: 



3-(3c+5)=2(10-c)

We move all terms to the left:

3-(3c+5)-(2(10-c))=0

We add all the numbers together, and all the variables

-(3c+5)-(2(-1c+10))+3=0

We get rid of parentheses

-3c-(2(-1c+10))-5+3=0



We calculate terms in parentheses: -(2(-1c+10)), so:

2(-1c+10)

We multiply parentheses

-2c+20

Back to the equation:

-(-2c+20)



We add all the numbers together, and all the variables

-3c-(-2c+20)-2=0

We get rid of parentheses

-3c+2c-20-2=0

We add all the numbers together, and all the variables

-1c-22=0

We move all terms containing c to the left, all other terms to the right

-c=22

c=22/-1

c=-22

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