4(3q+10)=6(2q-1)

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Solution for 4(3q+10)=6(2q-1) equation: 



4(3q+10)=6(2q-1)

We move all terms to the left:

4(3q+10)-(6(2q-1))=0

We multiply parentheses

12q-(6(2q-1))+40=0



We calculate terms in parentheses: -(6(2q-1)), so:

6(2q-1)

We multiply parentheses

12q-6

Back to the equation:

-(12q-6)



We get rid of parentheses

12q-12q+6+40=0

We add all the numbers together, and all the variables

46!=0

There is no solution for this equation

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