3(3c-2)=3(2c+5)

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Solution for 3(3c-2)=3(2c+5) equation: 



3(3c-2)=3(2c+5)

We move all terms to the left:

3(3c-2)-(3(2c+5))=0

We multiply parentheses

9c-(3(2c+5))-6=0



We calculate terms in parentheses: -(3(2c+5)), so:

3(2c+5)

We multiply parentheses

6c+15

Back to the equation:

-(6c+15)



We get rid of parentheses

9c-6c-15-6=0

We add all the numbers together, and all the variables

3c-21=0

We move all terms containing c to the left, all other terms to the right

3c=21

c=21/3

c=7

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