3+2=3z-(2z-3)

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Solution for 3+2=3z-(2z-3) equation: 



3+2=3z-(2z-3)

We move all terms to the left:

3+2-(3z-(2z-3))=0

We add all the numbers together, and all the variables

-(3z-(2z-3))+5=0



We calculate terms in parentheses: -(3z-(2z-3)), so:

3z-(2z-3)

We get rid of parentheses

3z-2z+3

We add all the numbers together, and all the variables

z+3

Back to the equation:

-(z+3)



We get rid of parentheses

-z-3+5=0

We add all the numbers together, and all the variables

-1z+2=0

We move all terms containing z to the left, all other terms to the right

-z=-2

z=-2/-1

z=+2

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