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3x-4)/4-(x-5)/2=1
We move all terms to the left:
3x-4)/4-(x-5)/2-(1)=0
Domain of the equation: 4-(x!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
-(x!=-4
x∈R
3x+()/(-(x*2-1+4)+(-5)*4-x/(-(x*2-1+4)=0
We calculate terms in parentheses: +()/(-(x*2-1+4)+(-5)*4-x/(-(x*2-1+4), so:
)/(-(x*2-1+4)+(-5)*4-x/(-(x*2-1+4
We can not solve this equation
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