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(3x-2)+1=(22-x)+1
We move all terms to the left:
(3x-2)+1-((22-x)+1)=0
We add all the numbers together, and all the variables
(3x-2)-((-1x+22)+1)+1=0
We get rid of parentheses
3x-((-1x+22)+1)-2+1=0
We calculate terms in parentheses: -((-1x+22)+1), so:We add all the numbers together, and all the variables
(-1x+22)+1
We get rid of parentheses
-1x+22+1
We add all the numbers together, and all the variables
-1x+23
Back to the equation:
-(-1x+23)
3x-(-1x+23)-1=0
We get rid of parentheses
3x+1x-23-1=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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