(3-2x)+3(1-42)-4(1-5x)=2(1-3x.)

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Solution for (3-2x)+3(1-42)-4(1-5x)=2(1-3x.) equation:



(3-2x)+3(1-42)-4(1-5x)=2(1-3x.)
We move all terms to the left:
(3-2x)+3(1-42)-4(1-5x)-(2(1-3x.))=0
We add all the numbers together, and all the variables
(-2x+3)-4(-5x+1)-(2(-3x.+1))+3(-41)=0
We add all the numbers together, and all the variables
(-2x+3)-4(-5x+1)-(2(-3x.+1))-123=0
We multiply parentheses
(-2x+3)+20x-(2(-3x.+1))-4-123=0
We get rid of parentheses
-2x+20x-(2(-3x.+1))+3-4-123=0
We calculate terms in parentheses: -(2(-3x.+1)), so:
2(-3x.+1)
We multiply parentheses
-6x+2
Back to the equation:
-(-6x+2)
We add all the numbers together, and all the variables
18x-(-6x+2)-124=0
We get rid of parentheses
18x+6x-2-124=0
We add all the numbers together, and all the variables
24x-126=0
We move all terms containing x to the left, all other terms to the right
24x=126
x=126/24
x=5+1/4

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