1/3(x-7)=5x-4(x-1)+17/3

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Solution for 1/3(x-7)=5x-4(x-1)+17/3 equation: 



1/3(x-7)=5x-4(x-1)+17/3

We move all terms to the left:

1/3(x-7)-(5x-4(x-1)+17/3)=0



Domain of the equation: 3(x-7)!=0

x∈R



We calculate fractions


()/3x+(-(x+51xx)/3x=0

We add all the numbers together, and all the variables

()/3x+(-(+x+51xx)/3x=0

We multiply all the terms by the denominator


(-(+x+51xx)+()=0



We calculate terms in parentheses: +(-(+x+51xx)+(), so:

-(+x+51xx)+(

We add all the numbers together, and all the variables

-(+x+51xx)

We get rid of parentheses

-x-51xx

We add all the numbers together, and all the variables

-1x-51xx

Back to the equation:

+(-1x-51xx)



We get rid of parentheses

-1x-51xx=0

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