3(z-3)=-3z+9

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Solution for 3(z-3)=-3z+9 equation: 



3(z-3)=-3z+9

We move all terms to the left:

3(z-3)-(-3z+9)=0

We multiply parentheses

3z-(-3z+9)-9=0

We get rid of parentheses

3z+3z-9-9=0

We add all the numbers together, and all the variables

6z-18=0

We move all terms containing z to the left, all other terms to the right

6z=18

z=18/6

z=3

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