3(z+5)=2(z-5)

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Solution for 3(z+5)=2(z-5) equation: 



3(z+5)=2(z-5)

We move all terms to the left:

3(z+5)-(2(z-5))=0

We multiply parentheses

3z-(2(z-5))+15=0



We calculate terms in parentheses: -(2(z-5)), so:

2(z-5)

We multiply parentheses

2z-10

Back to the equation:

-(2z-10)



We get rid of parentheses

3z-2z+10+15=0

We add all the numbers together, and all the variables

z+25=0

We move all terms containing z to the left, all other terms to the right

z=-25

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