3(y-2)=3y+5-(y+4)

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Solution for 3(y-2)=3y+5-(y+4) equation: 



3(y-2)=3y+5-(y+4)

We move all terms to the left:

3(y-2)-(3y+5-(y+4))=0

We multiply parentheses

3y-(3y+5-(y+4))-6=0



We calculate terms in parentheses: -(3y+5-(y+4)), so:

3y+5-(y+4)

determiningTheFunctionDomain
3y-(y+4)+5

We get rid of parentheses

3y-y-4+5

We add all the numbers together, and all the variables

2y+1

Back to the equation:

-(2y+1)



We get rid of parentheses

3y-2y-1-6=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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