1/4(16a+28)=1/3(9a-6)

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Solution for 1/4(16a+28)=1/3(9a-6) equation: 



1/4(16a+28)=1/3(9a-6)

We move all terms to the left:

1/4(16a+28)-(1/3(9a-6))=0



Domain of the equation: 4(16a+28)!=0

a∈R





Domain of the equation: 3(9a-6))!=0

a∈R



We calculate fractions


(3a9/(4(16a+28)*3(9a-6)))+(-4a1/(4(16a+28)*3(9a-6)))=0



We calculate terms in parentheses: +(3a9/(4(16a+28)*3(9a-6))), so:

3a9/(4(16a+28)*3(9a-6))

We multiply all the terms by the denominator


3a9

We add all the numbers together, and all the variables

3a^9

We do not support eapression: a^9

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