2(n-4)=-4(n-3)

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Solution for 2(n-4)=-4(n-3) equation: 



2(n-4)=-4(n-3)

We move all terms to the left:

2(n-4)-(-4(n-3))=0

We multiply parentheses

2n-(-4(n-3))-8=0



We calculate terms in parentheses: -(-4(n-3)), so:

-4(n-3)

We multiply parentheses

-4n+12

Back to the equation:

-(-4n+12)



We get rid of parentheses

2n+4n-12-8=0

We add all the numbers together, and all the variables

6n-20=0

We move all terms containing n to the left, all other terms to the right

6n=20

n=20/6

n=3+1/3

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