6v+6(3v+4)=4(2v+2)

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Solution for 6v+6(3v+4)=4(2v+2) equation: 



6v+6(3v+4)=4(2v+2)

We move all terms to the left:

6v+6(3v+4)-(4(2v+2))=0

We multiply parentheses

6v+18v-(4(2v+2))+24=0



We calculate terms in parentheses: -(4(2v+2)), so:

4(2v+2)

We multiply parentheses

8v+8

Back to the equation:

-(8v+8)



We add all the numbers together, and all the variables

24v-(8v+8)+24=0

We get rid of parentheses

24v-8v-8+24=0

We add all the numbers together, and all the variables

16v+16=0

We move all terms containing v to the left, all other terms to the right

16v=-16

v=-16/16

v=-1

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