22x-20=3(2x+4)

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Solution for 22x-20=3(2x+4) equation: 



22x-20=3(2x+4)

We move all terms to the left:

22x-20-(3(2x+4))=0



We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

22x-6x-12-20=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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