3(y-2)=2(y-1)=3

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Solution for 3(y-2)=2(y-1)=3 equation: 



3(y-2)=2(y-1)=3

We move all terms to the left:

3(y-2)-(2(y-1))=0

We multiply parentheses

3y-(2(y-1))-6=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We get rid of parentheses

3y-2y+2-6=0

We add all the numbers together, and all the variables

y-4=0

We move all terms containing y to the left, all other terms to the right

y=4

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