13(2x+3)-5(3x-8)=12-2(3x+1)

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Solution for 13(2x+3)-5(3x-8)=12-2(3x+1) equation: 



13(2x+3)-5(3x-8)=12-2(3x+1)

We move all terms to the left:

13(2x+3)-5(3x-8)-(12-2(3x+1))=0

We multiply parentheses

26x-15x-(12-2(3x+1))+39+40=0



We calculate terms in parentheses: -(12-2(3x+1)), so:

12-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+12

We multiply parentheses

-6x-2+12

We add all the numbers together, and all the variables

-6x+10

Back to the equation:

-(-6x+10)



We add all the numbers together, and all the variables

11x-(-6x+10)+79=0

We get rid of parentheses

11x+6x-10+79=0

We add all the numbers together, and all the variables

17x+69=0

We move all terms containing x to the left, all other terms to the right

17x=-69

x=-69/17

x=-4+1/17

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