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x2+1=4x-6
We move all terms to the left:
x2+1-(4x-6)=0
We add all the numbers together, and all the variables
x^2-(4x-6)+1=0
We get rid of parentheses
x^2-4x+6+1=0
We add all the numbers together, and all the variables
x^2-4x+7=0
a = 1; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·1·7
Δ = -12
Delta is less than zero, so there is no solution for the equation
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