2y+5/2=27/2

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Solution for 2y+5/2=27/2 equation: 



2y+5/2=27/2

We move all terms to the left:

2y+5/2-(27/2)=0

We add all the numbers together, and all the variables

2y+5/2-(+27/2)=0

We get rid of parentheses

2y+5/2-27/2=0

We multiply all the terms by the denominator


2y*2+5-27=0

We add all the numbers together, and all the variables

2y*2-22=0

Wy multiply elements

4y-22=0

We move all terms containing y to the left, all other terms to the right

4y=22

y=22/4

y=5+1/2

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