3(y-2)=-3y+6(y-1)

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Solution for 3(y-2)=-3y+6(y-1) equation: 



3(y-2)=-3y+6(y-1)

We move all terms to the left:

3(y-2)-(-3y+6(y-1))=0

We multiply parentheses

3y-(-3y+6(y-1))-6=0



We calculate terms in parentheses: -(-3y+6(y-1)), so:

-3y+6(y-1)

We multiply parentheses

-3y+6y-6

We add all the numbers together, and all the variables

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

3y-3y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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