-(z-6)+(3z+1)=-3(z+1)

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Solution for -(z-6)+(3z+1)=-3(z+1) equation: 



-(z-6)+(3z+1)=-3(z+1)

We move all terms to the left:

-(z-6)+(3z+1)-(-3(z+1))=0

We get rid of parentheses

-z+3z-(-3(z+1))+6+1=0



We calculate terms in parentheses: -(-3(z+1)), so:

-3(z+1)

We multiply parentheses

-3z-3

Back to the equation:

-(-3z-3)



We add all the numbers together, and all the variables

2z-(-3z-3)+7=0

We get rid of parentheses

2z+3z+3+7=0

We add all the numbers together, and all the variables

5z+10=0

We move all terms containing z to the left, all other terms to the right

5z=-10

z=-10/5

z=-2

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